If f(Pi/8) = 0 and f '(x) = 3/2 + (cos (2x))^2, find the equation of the tangent line to the graph of this function at the point (Pi/8, 0).
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Originally Posted by zweevu If f(Pi/8) = 0 and f '(x) = 3/2 + (cos (2x))^2, find the equation of the tangent line to the graph of this function at the point (Pi/8, 0). A tangent line has the following form for all functions Where is the point at which you want the line to be tangent and m= the derivative evalauted at the point So I leave it to you to plug it into the formula I provided
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