Math Help - [SOLVED] finding limits

1. [SOLVED] finding limits

i got 3.434 which is wreong

i got 1 which was wrong??

very confuised

2. Not sure about the first one, but for the second one, you need to use L'hopital's rule, and you should get 6/5.

3. Originally Posted by kyleu03

i got 3.434 which is wreong

i got 1 which was wrong??

very confuised
$\lim_{x \to 0} \frac{\tan(6x)}{\tan(2x)}
$

use L'Hopital ...

$\lim_{x \to 0} \frac{6\sec^2(6x)}{2\sec^2(2x)} = \frac{6}{2} = 3
$

hint for #2 ...

$x^n-1 = (x-1)(x^{n-1} + x^{n-2} + ... + x^2 + x + 1)$