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Math Help - [SOLVED] finding limits

  1. #1
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    [SOLVED] finding limits



    i got 3.434 which is wreong




    i got 1 which was wrong??

    very confuised
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  2. #2
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    Not sure about the first one, but for the second one, you need to use L'hopital's rule, and you should get 6/5.
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  3. #3
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    Quote Originally Posted by kyleu03 View Post


    i got 3.434 which is wreong




    i got 1 which was wrong??

    very confuised
    \lim_{x \to 0} \frac{\tan(6x)}{\tan(2x)}<br />

    use L'Hopital ...

    \lim_{x \to 0} \frac{6\sec^2(6x)}{2\sec^2(2x)} = \frac{6}{2} = 3<br />



    hint for #2 ...

    x^n-1 = (x-1)(x^{n-1} + x^{n-2} + ... + x^2 + x + 1)
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