If y = 3x^3 + 2x and dx/dt = 5, then find dy/dt when x = 2: My work: y = 3x^3 +2x dy/dt = 9x^2(dx/dt) + 2 dy/dt = 9(4)(5) + 5 dy/dt = 182 What did I do wrong here?
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Originally Posted by Maziana If y = 3x^3 + 2x and dx/dt = 5, then find dy/dt when x = 2: My work: y = 3x^3 +2x dy/dt = 9x^2(dx/dt) + 2(dx/dt) ...
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