The region bounded by y=e^{-x^2}, y=0, x=0, and x=1 is revolved about the y-axis. Find the volume of the resulting solid.
so it should be the integral (0,1) of e^(-x^2). u=-x^2, du=-2xdx, coefficient=-1/2
therefore, (-1/2) int(0,1) e^u*du = (-1/2) e^u evaluated at |(0,1)
so, ((-e^-1)/2) - ((-e^0)/2)= -.1839397206 - (-.5) = .3160602794
multiply this by pi to get my answer, which was .9929326519, but incorrect.
what am i doing wrong?