hey we just started doing Derivatives in Math and im a tad bit lost..... i tried reading your calculus introduction section but im having trouble following it .....

so i have to do this questiong

$F(x) = x^3 + 2x^2 + 4x + 3$

i have to find the derivatives using the first principal and limits

this formula $f'(x) = (f(x+h) - f(x))/h$ Where h is approaching 0...i know this is practically asking you the answer but...i dont know how to go about this
could anyone pleas explain what i need to do.....

2. Consider the terms separately

Hints for f(x) = 2 x^2

f(x+h) = 2(x+h)^2

[f(x+h) - f(x)]/h = 2[ (x+h)^2 -x^2]/h = 2[(x+h-x)(x+h+x)]/h
= 2h(2x+h)/h = 2(2x+h)

What happens as h ->0 ?

f(x) = x^3 f(x+h) = (x+h)^3

[f(x+h)- f(x)]/h = (x+h-x)[(x+h)^2 +(x+h)x + x^2]/h

= (x+h)^2 +(x+h)x + x^2]

What happens as h -> 0