# Math Help - Trig LIMITS help needed!!

1. ## Trig LIMITS help needed!!

any one know how to do the question in the picture, answer back, becaus ei have no idea how to do it..

2. you need to factorise which is inside of the arctan function.

3. i dont get what you are saying, but when i simplify, then i get
lim x -> 2 arctan(x+2/5x)
then i put in 2, and get 4/10, then i do arctan of that and get 21.804
but this is the wrong answer, how do i properly do this..???

4. Originally Posted by Sneaky
i dont get what you are saying, but when i simplify, then i get
lim x -> 2 arctan(x+2/5x)
then i put in 2, and get 4/10, then i do arctan of that and get 21.804
but this is the wrong answer, how do i properly do this..???

Then they're wrong and you're right: it is Arctan(2/5). Perhaps the answer is given in radians instead of degrees? Then it'd be 0.3805 rad.

Tonio