Trig LIMITS help needed!!

• Oct 6th 2009, 11:38 AM
Sneaky
Trig LIMITS help needed!!
any one know how to do the question in the picture, answer back, becaus ei have no idea(Surprised)(Surprised) how to do it..
• Oct 6th 2009, 12:03 PM
Krizalid
you need to factorise which is inside of the arctan function.
• Oct 6th 2009, 12:06 PM
Sneaky
i dont get what you are saying, but when i simplify, then i get
lim x -> 2 arctan(x+2/5x)
then i put in 2, and get 4/10, then i do arctan of that and get 21.804
but this is the wrong answer, how do i properly do this..???(Angry)(Angry)
• Oct 6th 2009, 01:01 PM
tonio
Quote:

Originally Posted by Sneaky
i dont get what you are saying, but when i simplify, then i get
lim x -> 2 arctan(x+2/5x)
then i put in 2, and get 4/10, then i do arctan of that and get 21.804
but this is the wrong answer, how do i properly do this..???(Angry)(Angry)

Then they're wrong and you're right: it is Arctan(2/5). Perhaps the answer is given in radians instead of degrees? Then it'd be 0.3805 rad.

Tonio