Lim [sqrt (x^2 + 3x)] / (4-4x)

x> -inf

-inf means -infinity and its the square root of only (x^2 + 3x)

How do I even do a problem like this? I found -1/4 which is wrong

according to my webwork site.

Then I found -inf which is also wrong since it sais the point im finding will be the horizontal asymptote.

Please help!