Just like with rational fns consider the ratio of highest powered terms
Lim [sqrt (x^2 + 3x)] / (4-4x)
x> -inf
Recall sqrt(x^2) = |x| = -x for x <0 since x-> negative inf we have
= lim |x|/(-4x) = lim-x/-4x = 1/4
Lim [sqrt (x^2 + 3x)] / (4-4x)
x> -inf
-inf means -infinity and its the square root of only (x^2 + 3x)
How do I even do a problem like this? I found -1/4 which is wrong
according to my webwork site.
Then I found -inf which is also wrong since it sais the point im finding will be the horizontal asymptote.
Please help!