# Thread: Help on limit at infinite problem?

1. ## Help on limit at infinite problem?

Lim [sqrt (x^2 + 3x)] / (4-4x)
x> -inf

-inf means -infinity and its the square root of only (x^2 + 3x)

How do I even do a problem like this? I found -1/4 which is wrong
according to my webwork site.
Then I found -inf which is also wrong since it sais the point im finding will be the horizontal asymptote.