I understand in theory how to do this...it's just the particular problem that's throwing me.
Question: Find the equation of the normal line to the graph of
at the point where it crosses the x-axis.
My Attempt:
So
f(x) crosses the x-axis at pretty much x = 0 I think.
so do I plug in 0 for x and solve in the original equation like this?
Giving the point (0,0)
then plug that into y = mx + b
I get
so
Does that mean the tangent line is just
?
Making the normal line
?
Is that right? Or am I doing this completely wrong?