I understand in theory how to do this...it's just the particular problem that's throwing me.

**Question: **Find the equation of the normal line to the graph of

at the point where it crosses the x-axis.

**My Attempt:**
So

f(x) crosses the x-axis at pretty much x = 0 I think.

so do I plug in 0 for x and solve in the original equation like this?

Giving the point (0,0)

then plug that into y = mx + b

I get

so

Does that mean the tangent line is just

?

Making the normal line

?

Is that right? Or am I doing this completely wrong?