h(y)=(b/(a+y^4))^4
find h'(y)
I was using the chain rule
h(x)=f(g(x))
h'(x)=f'(g(x))*g'(x)
and I got...
4(b/(a+y^4))((-4by^3)/(a+y^4)^2)
could someone tell me the answer, or if you have time, tell me step by step what to do?
h(y)=(b/(a+y^4))^4
find h'(y)
I was using the chain rule
h(x)=f(g(x))
h'(x)=f'(g(x))*g'(x)
and I got...
4(b/(a+y^4))((-4by^3)/(a+y^4)^2)
could someone tell me the answer, or if you have time, tell me step by step what to do?