f'(x) = [6x(2x+1) - 6x^2]/(2x+1)^2 = 6[x^2 + x]/(2x+1)^2 = 4/3 ==>

[x^2 + x)]/(2x + 1) = 2/9 ==> 9x^2 + 9x = 4x + 2 ==> 9x^2 + 5x - 2 = 0

This quadratic's discriminant is D = 25 + 72 = 97 ==> there are two real solutions:

x_1,2 = [-5 (+/-) Sqrt(97)]/18 , and since both these points are different

from -1/2, where the function isn't defined, then we're done.

Tonio