# Thread: volume of solid of revolution

1. ## volume of solid of revolution

consider $B>1.$

compute the volume of revolution given the curve $y=\sqrt xe^{-x^2}$ between $y=\sqrt Be^{-B^2}$ and $y=e^{-1}$ revolving the $x$ axis.

don't know how to set up the integral.

thanks for the help.

2. Originally Posted by palpyko
consider $B>1.$

compute the volume of revolution given the curve $y=\sqrt xe^{-x^2}$ between $y=\sqrt Be^{-B^2}$ and $y=e^{-1}$ revolving the $x$ axis.

don't know how to set up the integral.

thanks for the help.
The volume of a solid which is produced by revolution of the curve y = f(x) about the x-axis is calculated by

$V = \pi \int y^2 dx$

From $y=e^{-1}$ you know that x = 1 and

from $y=\sqrt Be^{-B^2}$ you know that x = B > 1

Use the formula given above to calculate the volume. Use integration by substitution.