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Math Help - Simple Velocity Problem

  1. #1
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    Simple Velocity Problem

    If a stone is thrown vertically upward with a velocity of 10 m/s, its height in meters after t seconds is h = 10t - 0.83t^2. What is the velocity of the stone after it has risen 25 meters?

    I am not sure how to do this problem. I would guess it involves finding f'(h) = 10 - 1.66t, but please show me how to find the answer in a way that makes sense.
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  2. #2
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    Quote Originally Posted by Maziana View Post
    If a stone is thrown vertically upward with a velocity of 10 m/s, its height in meters after t seconds is h = 10t - 0.83t^2. What is the velocity of the stone after it has risen 25 meters?

    I am not sure how to do this problem. I would guess it involves finding f'(h) = 10 - 1.66t, but please show me how to find the answer in a way that makes sense.

    The derivative of distance (height in this case) is velocity. You found the derivative. So you have an equation for the velocity at any time=t. Now you need to find t when h=25, which you can do because you have the equation for h, and then plug that value into the derivative
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