1. ## Simple Velocity Problem

If a stone is thrown vertically upward with a velocity of 10 m/s, its height in meters after t seconds is h = 10t - 0.83t^2. What is the velocity of the stone after it has risen 25 meters?

I am not sure how to do this problem. I would guess it involves finding f'(h) = 10 - 1.66t, but please show me how to find the answer in a way that makes sense.

2. Originally Posted by Maziana
If a stone is thrown vertically upward with a velocity of 10 m/s, its height in meters after t seconds is h = 10t - 0.83t^2. What is the velocity of the stone after it has risen 25 meters?

I am not sure how to do this problem. I would guess it involves finding f'(h) = 10 - 1.66t, but please show me how to find the answer in a way that makes sense.

The derivative of distance (height in this case) is velocity. You found the derivative. So you have an equation for the velocity at any time=t. Now you need to find t when h=25, which you can do because you have the equation for h, and then plug that value into the derivative