Originally Posted by
calcbeg Hi
The goal is to find the average value of the function h (t) = 1/(e^2t) over the interval (0,1)
So havg (1-0) = S a=0; b=1 e^-2t dt
So I am assuming I should do some substitution
let u = e^-2t then du =-2e^-2t dt so du/-2 = e^-2t dt
Then havg = S a=0;b=1 du/-2 = -1/2 S du = -1/2 (u) a=0;b=1
So then -1/2 (e^-2t) a=0;b=1
= -1/2 (e^-2 - e^0) So far, so good
= -1/(2e) + 1 you simplified incorrectly
Did I do this correctly???
Thanks
Calculus beginner - who no longer likes the letter e