$\displaystyle {y^{IV}} = {e^x}(4 + x) + \sin (x)

$

$\displaystyle y'''(0) = 2,y''(0) = 2,y'(0) = 2,y(0) = 2

$

I'm not sure where to begin. Should I do product rule or something else?

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- Oct 4th 2009, 09:39 AMgenlovesmusic09solution to the following intial value problem
$\displaystyle {y^{IV}} = {e^x}(4 + x) + \sin (x)

$

$\displaystyle y'''(0) = 2,y''(0) = 2,y'(0) = 2,y(0) = 2

$

I'm not sure where to begin. Should I do product rule or something else? - Oct 4th 2009, 10:11 AMScott H
Integrating $\displaystyle y^{IV}$ four times will work. Remember the arbitrary constants. :)