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Math Help - solving a integral with x to the x

  1. #1
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    solving a integral with x to the x

    \int_1^2 {{x^x}(1 + \ln x)} dx<br />
    not sure where to begin
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  2. #2
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    Quote Originally Posted by genlovesmusic09 View Post
    \int_1^2 {{x^x}(1 + \ln x)} dx<br />
    not sure where to begin
    Notice that if u = x^x then du = x^x(1 + \ln x)\,dx
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  3. #3
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    \int_1^2 {du}  = [{x^x}]_1^2 = 4 - 1 = 3<br />

    ?
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  4. #4
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    yes.
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