# Math Help - Derivatives with both a and y

1. ## Derivatives with both a and y

Hello!
I've tried to solve this problem, but I am not completely sure how to differentiate when there is both x and y.
I would appreciate your help and explanation

The problem:
2x^2 - x - y^2 = 0

dy/dx: x = 1 and y = 1
= ?

The correct answer is apparently: 3/2

Thanks

2. simply my friend

first things first, u need to separate the variables and make this eq in terms of y

$y = sqrt(2x^2-x)$

now take the derivative of both sides
the RHS is a bit tricky, its a chain rule problem.
its turns out to be

$dy = (1/(2(2x^2-x)^1/2 )*(4x-1)$

gah i hate this LATEX stuff... im trying to make this look right

dy = (1/2)*2(2x^2-x)^1/2 * (4x-1)

3. thank you very much for your help
But what does "sqrt" mean?

4. sqrt = square root

sorry i thought that it was the coding LATEX used