Originally Posted by

**mvho** Question:

The function $\displaystyle Y=K^\frac{1}{3}L^\frac{2}{3}$ is Given.

a) Find $\displaystyle \frac{dY}{dL}$

b) Solve for **"L"** in the equation: $\displaystyle \frac{2}{3}K^\frac{1}{3}L^\frac{-1}{3}=\frac{W}{P}$

What I have so far:

a) $\displaystyle K^\frac{1}{3}\frac{2}{3}L^\frac{-1}{3}$

b) I am unsure, but would I would divide $\displaystyle \frac{W}{P}$ by K. Only thing is, I am sure you can't just ignore that exponent can you?

Help! I need a refresher. That much is obvious.