y=Ln(e^x + e^-x) , so far I got y=1/e^x-1/e^-x . I Dont think its correct though. please help
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Originally Posted by bgonzal8 y=Ln(e^x + e^-x) , so far I got y=1/e^x-1/e^-x . I Dont think its correct though. please help in general so
Originally Posted by Amer in general so Thank you
Originally Posted by Amer in general so = tanh(x)
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