$\displaystyle \int_{-5}^5 \frac{2}{x^3} dx$

the answer i got is 0.

the answer in the back of the book says: Does not exist

what did i do incorrectly?

This is what I did: $\displaystyle \int_{-5}^5 \frac{2}{x^3} dx$

= $\displaystyle \frac{-1}{x^2}|_{-5}^5$

=$\displaystyle \frac{-1}{(5)^2}-(\frac{-1}{(-5)^2})$

=$\displaystyle \frac{-1}{25}+\frac{1}{25}$

=0