Find the derivative of the function. h(x)=(10/sqrt x) - (2x)
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If you rewrite the function as h(x) = 10(x^-0.5) - 2x you might be able to see how to do it from there. If not.... look below. {h'(x) = -5(x^-3/2) - 2}
h(X) = (10/sqrt(X)) - 2X = 10X^-0.5 -(2X) d/dx = -5X^-3/2 - (2) = -(5/sqrt(X^3)) -2
Originally Posted by kdstalnaker Find the derivative of the function. h(x)=(10/sqrt x) - (2x) I'll suggest what the others have, but I'll put it in Latex for you $\displaystyle h(x)=10(x^{-\frac{1}{2}})-2x$ Power rule my friend. You're finding $\displaystyle \frac{dh}{dx}$, just for notation's sake.
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