1. Lost!

Find the derivative of the function.

h(x)=(10/sqrt x) - (2x)

2. If you rewrite the function as

h(x) = 10(x^-0.5) - 2x

you might be able to see how to do it from there.

If not.... look below.

{h'(x) = -5(x^-3/2) - 2}

3. try this

h(X) = (10/sqrt(X)) - 2X

= 10X^-0.5 -(2X)

d/dx = -5X^-3/2 - (2)

= -(5/sqrt(X^3)) -2

4. Originally Posted by kdstalnaker
Find the derivative of the function.

h(x)=(10/sqrt x) - (2x)
I'll suggest what the others have, but I'll put it in Latex for you

$h(x)=10(x^{-\frac{1}{2}})-2x$

Power rule my friend.

You're finding $\frac{dh}{dx}$, just for notation's sake.