Results 1 to 4 of 4

Math Help - Lost!

  1. #1
    Newbie
    Joined
    Apr 2005
    Posts
    23

    Lost!

    Find the derivative of the function.

    h(x)=(10/sqrt x) - (2x)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Oct 2005
    Posts
    36
    If you rewrite the function as

    h(x) = 10(x^-0.5) - 2x

    you might be able to see how to do it from there.

    If not.... look below.

    {h'(x) = -5(x^-3/2) - 2}
    Follow Math Help Forum on Facebook and Google+

  3. #3
    ben
    ben is offline
    Newbie
    Joined
    Sep 2005
    Posts
    5

    Post try this

    h(X) = (10/sqrt(X)) - 2X

    = 10X^-0.5 -(2X)

    d/dx = -5X^-3/2 - (2)

    = -(5/sqrt(X^3)) -2
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Joined
    Oct 2005
    From
    Earth
    Posts
    1,599
    Quote Originally Posted by kdstalnaker
    Find the derivative of the function.

    h(x)=(10/sqrt x) - (2x)
    I'll suggest what the others have, but I'll put it in Latex for you

    h(x)=10(x^{-\frac{1}{2}})-2x

    Power rule my friend.

    You're finding \frac{dh}{dx}, just for notation's sake.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. I am lost, please help
    Posted in the Trigonometry Forum
    Replies: 6
    Last Post: February 5th 2010, 02:35 AM
  2. I'm a little lost
    Posted in the Calculus Forum
    Replies: 1
    Last Post: January 21st 2010, 08:28 PM
  3. A Bit Lost...
    Posted in the Calculus Forum
    Replies: 2
    Last Post: October 29th 2009, 05:44 PM
  4. i am so lost help me please
    Posted in the Advanced Algebra Forum
    Replies: 1
    Last Post: September 23rd 2009, 10:45 AM
  5. Lost...
    Posted in the Advanced Statistics Forum
    Replies: 2
    Last Post: December 11th 2008, 02:41 PM

Search Tags


/mathhelpforum @mathhelpforum