In the theory of relativity, the mass of a particle with velocity v is m = m0 / sqrt(1-v^2 / c^2) where m0 is mass of the particle at rest and c is the speed of light. What happens as v approaches as c^-? Thanks for any feedback!
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Originally Posted by ty2391 In the theory of relativity, the mass of a particle with velocity v is m = m0 / sqrt(1-v^2 / c^2) where m0 is mass of the particle at rest and c is the speed of light. What happens as v approaches as c^-? Thanks for any feedback! m --> +oo
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