How would I go about writing $1/2-1/3+1/4-1/5+1/6$ in summation notation?
How would I go about writing $1/2-1/3+1/4-1/5+1/6$ in summation notation?
$\sum_{n=2}^6 \frac{(-1)^n}{n}$
The $(-1)^n$ term gives the alternating signs.