Results 1 to 2 of 2

Math Help - Derivative using the quotient rule

  1. #1
    Newbie
    Joined
    Sep 2009
    Posts
    13

    Derivative using the product rule

    I am familiar with the equation, but I am having trouble working out the entire answer.

    "Differentiate using the Product Rule":

    h(t)= \sqrt[3]{t}(t^2+4)


    Thanks!
    Last edited by mr fantastic; September 30th 2009 at 10:01 PM. Reason: Formalised the edit made by the OP
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by cynlix View Post
    whoops, sorry. I meant product rule.


    This is what I have so far...


    = (\frac{1}{3t^\frac{-2}{3}})(t^2+4) + (t^\frac{1}{3}) (1) Mr F says: This should either be {\color{red}(\frac{1}{3t^\frac{2}{3}})(t^2+4) + (t^\frac{1}{3}) (2t)} or {\color{red}(\frac{1}{3} t^\frac{-2}{3})(t^2+4) + (t^\frac{1}{3}) (2t)}. Everything that followed will be wrong.

    [snip]
    Putting 1 for the derivative of t^2 + 4 was a particularly bad mistake.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: June 1st 2010, 04:28 AM
  2. derivative - using quotient rule
    Posted in the Calculus Forum
    Replies: 5
    Last Post: March 18th 2010, 02:18 AM
  3. Replies: 5
    Last Post: March 4th 2010, 05:54 PM
  4. derivative using quotient rule
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 16th 2010, 06:50 PM
  5. Derivative Quotient Rule
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 15th 2008, 03:36 PM

Search Tags


/mathhelpforum @mathhelpforum