y=6x^ln(x) Before I take the derivative, is this right? ln(y)=ln(x)[ln(6x)]
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Originally Posted by yeloc y=6x^ln(x) Before I take the derivative, is this right? ln(y)=ln(x)[ln(6x)] No. $\displaystyle \ln (y) = \ln \left( 6 x^{ln(x)} \right) = \ln (6) + \ln \left( x^{ln(x)} \right) = \ln (6) + \ln (x) \ln (x) $.
Ok that would explain it. so the derivative would be: y'=[(2ln(x))/x]*[6x^ln(x)] ?
Originally Posted by yeloc Ok that would explain it. so the derivative would be: y'=[(2ln(x))/x]*[6x^ln(x)] ? Yes.
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