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Math Help - Area/Perimeter Function Problem

  1. #1
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    Question Area/Perimeter Function Problem

    I posted a problem last week with this same picture and got some great help- many thanks ahead of time!

    Find the perimeter function in terms of x if the area function is A(x)= 28 sq. ft.
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  2. #2
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    So, i guess your area is
    P(x) = pi*x + 2y + 2x

    now substitute A(x) for 28
    and get your answer in terms of x

    I hope I'm right.
    Last edited by Arturo_026; September 30th 2009 at 07:37 PM.
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  3. #3
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    Would the area be 2xy + 1/2pi * (x)^2??
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  4. #4
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    Quote Originally Posted by kittykat616 View Post
    Would the area be 2xy + 1/2pi * (x)^2??
    Yes, considering that the radius os the semicircle is x
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  5. #5
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    Alright. So would the peimeter be (2x+2y)+ Pi (x)? Then put the area function every where there is x??
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  6. #6
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    I misunderstood your question in the first post, sorry.

    Yes, with the perimeter function find the value of y in terms of x and then substitute that in the area function.
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  7. #7
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    So, the value of y in terms of x would be

    x=2y + 1/2pi(x) , right?

    Sorry for so many questions!
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