I posted a problem last week with this same picture and got some great help- many thanks ahead of time! Find the perimeter function in terms of x if the area function is A(x)= 28 sq. ft.
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So, i guess your area is P(x) = pi*x + 2y + 2x now substitute A(x) for 28 and get your answer in terms of x I hope I'm right.
Last edited by Arturo_026; September 30th 2009 at 08:37 PM.
Would the area be 2xy + 1/2pi * (x)^2??
Originally Posted by kittykat616 Would the area be 2xy + 1/2pi * (x)^2?? Yes, considering that the radius os the semicircle is x
Alright. So would the peimeter be (2x+2y)+ Pi (x)? Then put the area function every where there is x??
I misunderstood your question in the first post, sorry. Yes, with the perimeter function find the value of y in terms of x and then substitute that in the area function.
So, the value of y in terms of x would be x=2y + 1/2pi(x) , right? Sorry for so many questions!
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