∇∙(φuu) where φ is a scalar and u is a vector and ∇∙(T×u) where T is a second order tensor and u is a vector.
Last edited by oxxiissiixxo; September 30th 2009 at 04:59 PM.
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I found out that the solution for ∇∙(φuu) is φu∙∇u+u[∇∙(φu)] for this the solution is just seemed like ∇∙(φuu) is φu∙∇u+u[∇∙(φu)] ∇∙(AB) is A∙∇B+B[∇∙(A)] but I just can't fill in the step correctly in between and ∇∙(T×u) is -u×(∇∙T)+T
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