My professor did not explain how to find the derivation of an inverse trig function very well, so I need some basic help in understanding what steps to take. I understand the derivations, and the need to use the chain rule and sometimes the product/quotient rule, but I don't understand these problems:
y = arcsin(2x +1)
Would this be the next step? But then what?: y' = 1/ (1 - ((2x+1)^2)
y = arccos(e^2x)
Other than plugging this into the formula for the derivative of arccos, I don't know what to do...
Also, is this implicit derivation problem? If so, why?:
ysin(x^2) = xsin(y^2)
ycosx^2 + y'sinx^2 = xcosy^2(2yy') +siny^2
y'sinx^2 - 2xyy'cosy^2 = -ycosx^2 +siny^2
ect, take out y' and solve...
yes on implicit ...