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Math Help - trig functions need help asap!1

  1. #1
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    trig functions need help asap!1

    these are due at 5 ET and i cant get them!!!

    Express the given quantity as a single logarithm.
    ln(a + b) + ln(a - b) - 3 ln(c)


    Solve each equation for x. (a) e4x + 6 - 2 = 0
    x =


    (b) ln(8 - 8x) = -4
    x =
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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by kyleu03 View Post
    these are due at 5 ET and i cant get them!!!

    Express the given quantity as a single logarithm.
    ln(a + b) + ln(a - b) - 3 ln(c)


    Solve each equation for x. (a) e4x + 6 - 2 = 0
    x =


    (b) ln(8 - 8x) = -4
    x =
    1
    k\,ln(a) = ln(a^k)

    ln(a) + ln(b) = ln(ab)

    ln(a) - ln(b) = ln(\frac{a}{b})

    2
    e^{4x} = -4

    This equation has no real solutions.

    3.

    8-8x = e^{-4}

    Solve for x like a normal linear equation
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  3. #3
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    Quote Originally Posted by e^(i*pi) View Post
    1
    k\,ln(a) = ln(a^k)

    ln(a) + ln(b) = ln(ab)

    ln(a) - ln(b) = ln(\frac{a}{b})

    2
    e^{4x} = -4

    This equation has no real solutions.

    3.

    8-8x = e^{-4}

    Solve for x like a normal linear equation
    1 and 2 were both wrong
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  4. #4
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    Quote Originally Posted by kyleu03 View Post
    1 and 2 were both wrong
    The reply to question 1 was reminding you of rules that you're expected to know and be able to apply.

    I have no doubt that the reply to question 2 would have been correct if you had bothered to format your equation correctly. I assume the equation was meant to be e^(4x + 6) - 2 = 0. If your equation is not formatted correctly it should come as no surprise that it will be misunderstood.

    Be that as it may, these questions look like they're part of an assignment that counts towards your final grade. MHF policy is not to give help for such questions since it's meant to be your own work.

    Thread closed.
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