# Thread: trig functions need help asap!1

1. ## trig functions need help asap!1

these are due at 5 ET and i cant get them!!!

Express the given quantity as a single logarithm.
ln(a + b) + ln(a - b) - 3 ln(c)

Solve each equation for x. (a) e4x + 6 - 2 = 0
x =

(b) ln(8 - 8x) = -4
x =

2. Originally Posted by kyleu03
these are due at 5 ET and i cant get them!!!

Express the given quantity as a single logarithm.
ln(a + b) + ln(a - b) - 3 ln(c)

Solve each equation for x. (a) e4x + 6 - 2 = 0
x =

(b) ln(8 - 8x) = -4
x =
1
$\displaystyle k\,ln(a) = ln(a^k)$

$\displaystyle ln(a) + ln(b) = ln(ab)$

$\displaystyle ln(a) - ln(b) = ln(\frac{a}{b})$

2
$\displaystyle e^{4x} = -4$

This equation has no real solutions.

3.

$\displaystyle 8-8x = e^{-4}$

Solve for x like a normal linear equation

3. Originally Posted by e^(i*pi)
1
$\displaystyle k\,ln(a) = ln(a^k)$

$\displaystyle ln(a) + ln(b) = ln(ab)$

$\displaystyle ln(a) - ln(b) = ln(\frac{a}{b})$

2
$\displaystyle e^{4x} = -4$

This equation has no real solutions.

3.

$\displaystyle 8-8x = e^{-4}$

Solve for x like a normal linear equation
1 and 2 were both wrong

4. Originally Posted by kyleu03
1 and 2 were both wrong
The reply to question 1 was reminding you of rules that you're expected to know and be able to apply.

I have no doubt that the reply to question 2 would have been correct if you had bothered to format your equation correctly. I assume the equation was meant to be e^(4x + 6) - 2 = 0. If your equation is not formatted correctly it should come as no surprise that it will be misunderstood.

Be that as it may, these questions look like they're part of an assignment that counts towards your final grade. MHF policy is not to give help for such questions since it's meant to be your own work.

Thread closed.