y=(4x^2+1)^8/12x^3-1
I know that to start I must set y= u^8 and u= 4x^2+1
I must then use the quotient rule somehow...
Thanks so much for any and all help!
Hint:
$\displaystyle y= \frac{{{{\left( {4{x^2} + 1} \right)}^8}}}{{12{x^3} - 1}}.$
$\displaystyle \frac{{dy}}
{{dx}} = \frac{{\left( {12{x^3} - 1} \right) \cdot \frac{d}
{{dx}}{{\left( {4{x^2} + 1} \right)}^8} - {{\left( {4{x^2} + 1} \right)}^8} \cdot \frac{d}
{{dx}}\left( {12{x^3} - 1} \right)}}
{{{{\left( {12{x^3} - 1} \right)}^2}}} = \ldots$