1/(2sqrt(5xy)) · 5y + 5x · Dx(y) + 2 · Dx(y) = 2y · Dx(y) + y^3 +3xy^2 · Dx(y)
The notation is a bit cumbersome but you did a good job
See attachment
sqrt(5xy) + 2y = y^2 + xy^3
so I got this far and now I am stuck:
d/dx ((5xy)^1/2 + 2y) = d/dx (y^2 + xy^3)
= 1/2(5xy)^1/2-1) Dx(5x) (y) + 5x Dx(y) + 2 Dx(y) = 2y Dx(y) + Dx(x) (y^3) + x (3y^2) Dx (y)
= 1/(2sqrt(5xy)) · 5y + 5x · Dx(y) + 2 · Dx(y) = 2y · Dx(y) + y^3 +3xy^2 · Dx(y)
=?
I'm wondering if I'm doing this right and where would I go from there?