given intergrate from 0 to 2pi
(sin t)^2 dz / jz
---------
5- 4 cos t
i achieve the C_-1 equation till
( z^2 + z^-2 - 2) ( -j )
----------------------- dz
-20z + 8z^2 + 8
The pole are 2 & 0.5. ( Only 0.5 is lying in |z|=1 )
But i can't get the final answer which is ( pi/4) when i sub z =0.5 into
( z^2 + z^-2 - 2) * (2pi)
------------------
-----20+16z
many thanks
ck