x2 + y2 + z2 ≤ 1
or r^2 +z^2 = 1 which is a sphere
x2 + y2 + z2 ≤ 1
is the solid ball 0 < r < 1 0 < theta < 2pi -1 < z < 1
Im trying to work out the answer to the following question
Describe the set in cylindrical coordinates.
x2 + y2 + z2 ≤ 1
you need to find the limit for r, theta and z.
so far i have found that 0 ≤ r ≤ 1 and pi/4 ≤ θ
i havent a clue how to find the rest, can anyone help me?