The tangent at P to the curve y=x^2 has gradient 3. Find the equation of the normal at P. The answer of this question is 12y=-4x+33 Please help me with this question, please
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Originally Posted by creatively12 The tangent at P to the curve y=x^2 has gradient 3. Find the equation of the normal at P. The answer of this question is 12y=-4x+33 Please help me with this question, please The slope of the tangent is given by . If this is 3 then the x value is The normal has slope . The equation for this through is and if you simplify you'll get the answer you give.
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