Can someone please show me how this derivative: f'(x) = x^3(18x) - (9)(x^2 - 3)(3x^2)/(x^3)^2 Simplifies to this: 9(9 - x^2)/ x^4 Because I am lost lol Here is the original equation: f(x)= 9(x^2-3)/x^3 Thanks
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Originally Posted by Jwd41190 Can someone please show me how this derivative: f'(x) = x^3(18x) - (9)(x^2 - 3)(3x^2)/(x^3)^2 Simplifies to this: 9(9 - x^2)/ x^4 Because I am lost lol Here is the original equation: f(x)= 9(x^2-3)/x^3 Thanks It's really easier if you expand
Thats still not right is it here it is from the book Here it is from the book: http://img121.imageshack.us/img121/3689/scn0001.jpg
Originally Posted by Danny It's really easier if you expand What I'm saying is I think that this way is the easiest. However, if you use th equotient rule then
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