use the chain rule to find the derivative of g(f(x)) at the indicated point a.

g(x,y)= (x^2 * y^3, 3x-y^2)

f(x,y)= (-y,x)

a=(3,2)

i did:

D(g) matrix

2x 3y^2

3 -2y

D(g(f(x,y))) matrix

-2y 3x^2

3 -2x

D(f) matrix

0 -1

1 0

^i have a feeling this matrix is where i went wrong?

D(g(f(x,y)) * D(f) matrix:

3x^2 2y

-2x -3

at (3,2):

27 4

-6 -3

the answer in the back is

108 108

-6 -3