Originally Posted by

**machi4velli** I have been struggling with this problem for a while:

A bullet passes through a piece of wood 0.1 m thick. It enters the wood at 400 m/s and leaves at 180 m/s. The velocity v of the bullet is assumed to obey the differential equation dv/dt = -kv^2 where k is a positive constant. How long does it take the bullet to pass through the wood?

I got this far:

dv/dt = -kv^2

-1/v = -kt + C

v = 1/(kt + C)

400 = v(0) = 1/(k(0) + C)

400 = 1/C

.0025 = C

v = 1/(kt + .0025)

From here, I am not sure what to do. I tried to find k by making v = dx/dt and solving the displacement equation, which turned out to be another dead end.

Any help would be appreciated. Thanks.