Thread: derivatives

Suppose that the function j' has an inflrction point at x=2. What, if anything does this imply about

(a) j"?

(b) j?

I do not understand derivatives. I know you have to base your answer off the information given but I don't understand how to do that. Is it like since x=2 that means j(x) > 0 so would j(2)=3 and j"(2)=-3. Im really not sure can someone please explain derivatives to me. Thank you

Originally Posted by asweet1

Suppose that the function j' has an inflrction point at x=2. What, if anything does this imply about

(a) j"?

(b) j?

you might help your understanding by researching the answers to these questions ...

1. what is a point of inflection?

2. how does one go about finding inflection points?

The point of inflection is x=2 and you find the inflection point when the concavity switches direction so it would be switching to concave down so would j''(2)= -3. I have yet to full grasp the concept of derivatives. Do you just make guess in order to get answers?

Originally Posted by asweet1

The point of inflection is x=2 and you find the inflection point when the concavity switches direction so it would be switching to concave down so would j''(2)= -3. I have yet to full grasp the concept of derivatives. Do you just make guess in order to get answers?

Wrong. At a point of inflection the double derivative is equal to zero. It would be wise to do the research suggested in an earlier post.