How to find the derivative of a function

**Rainy2Day** · September 27th 2009, 10:41 AM

I have to find the derivative of sqrt.(4-x^2), top half of a circle, at the point x=-1.

My teacher won't let me use the rules of differentiation. so I can't just take the 1st derivative and plug -1 in. (I found the 1st derivative so I know the answer is 1/sqrt.3 or .5773)

Is there any other way to find the derivative at that point? If so could you explain how to do it.

Thanks in advance.

**skeeter** · September 27th 2009, 10:57 AM

Originally Posted by Rainy2Day

I have to find the derivative of sqrt.(4-x^2), top half of a circle, at the point x=-1.

My teacher won't let me use the rules of differentiation. so I can't just take the 1st derivative and plug -1 in. (I found the 1st derivative so I know the answer is 1/sqrt.3 or .5773)

Is there any other way to find the derivative at that point? If so could you explain how to do it.

Thanks in advance.

definition of a derivative at a point ...

$f'(-1) = \lim_{x \to -1} \frac{f(x) - f(-1)}{x - (-1)}$