Results 1 to 3 of 3

Math Help - Tangent and normal

  1. #1
    Member
    Joined
    Jan 2008
    Posts
    118

    Tangent and normal

    to the curve, x^2 - sqrt(3) xy + 2y^2 = 5

    I got the slope to equal 0.

    Can someone help me out please?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,520
    Thanks
    1404
    Quote Originally Posted by Morgan82 View Post
    to the curve, x^2 - sqrt(3) xy + 2y^2 = 5

    I got the slope to equal 0.

    Can someone help me out please?
    What exactly are you trying to do?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Aug 2008
    Posts
    88
    The equation for the tangent plane at a point is:


    Find your partial derivatives, plug everything in, and simplify.

    To find the normal line to this tangent plane, you then want to define x, y, and z parametrically. They will all have the form:
    x\left(t \right)=x_{0}+f_{x}\left(x_{0},y_{0},z_{0} \right)

    except with the appropriate variable in place of x. You then solve each equation for t and set all 3 equations equal (since t=t=t, this must be true).
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. tangent and normal
    Posted in the Calculus Forum
    Replies: 1
    Last Post: March 9th 2011, 07:27 AM
  2. Tangent & Normal(Q6)
    Posted in the Pre-Calculus Forum
    Replies: 6
    Last Post: February 19th 2010, 09:17 PM
  3. Tangent & Normal (Q8b)
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: February 17th 2010, 01:52 PM
  4. Tangent & Normal Q11
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: February 17th 2010, 11:18 AM
  5. tangent & normal
    Posted in the Geometry Forum
    Replies: 7
    Last Post: January 18th 2009, 03:00 AM

Search Tags


/mathhelpforum @mathhelpforum