to the curve, x^2 - sqrt(3) xy + 2y^2 = 5
I got the slope to equal 0.
Can someone help me out please?
The equation for the tangent plane at a point is:
Find your partial derivatives, plug everything in, and simplify.
To find the normal line to this tangent plane, you then want to define x, y, and z parametrically. They will all have the form:
$\displaystyle x\left(t \right)=x_{0}+f_{x}\left(x_{0},y_{0},z_{0} \right)$
except with the appropriate variable in place of x. You then solve each equation for t and set all 3 equations equal (since t=t=t, this must be true).