Correct.
The system of equations
can be solved by linear combination. Hint: Multiple solutions will work.
Show that the vectors u [-1 1] v [2 1] w[3 3] are linearly dependent.
So, linearly dependent means that there is a solution for A,B,C that doesn't involve all zero's right?
So, -a + 2b + 3c = 0 and a + b + 3c = 0
I just solve these linear system of equations to show that the vectors are linearly dependent? Or am I completely wrong?
Thank you
Uhh, it has been a while since I solved a system of equations, especially with 3 variables.. is there a good method for doing this besides just "looking at it". I must be doing something wrong because I keep getting zero for all of the variables when I try to solve it..
Okay,
so if b = 2a, I subsitute it back into the equation and get 3a + 3c = 0
then if I solve this for a, I get a = -c..
No matter where I go with this, I end up with all zero answers. Is there something simple I am missing here? Maybe I need to look up system of linear equations?
Thank you