what is the derivative of e^(x)-1?

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- Sep 27th 2009, 07:52 AMmech.engineer.majorsimple derivative
what is the derivative of e^(x)-1?

- Sep 27th 2009, 07:55 AMDefunkt
If it's $\displaystyle f(x) = e^x - 1$, then $\displaystyle f'(x)=e^x$.

If it's $\displaystyle f(x)= e^{x-1}$, then $\displaystyle f'(x) = e^{x-1}$ - Sep 27th 2009, 07:56 AMskeeter
$\displaystyle y = e^x - 1$

$\displaystyle \frac{dy}{dx} = e^x$

$\displaystyle y = e^{x-1}$

$\displaystyle \frac{dy}{dx} = e^{x-1}$

in general ...

$\displaystyle \frac{d}{dx} [e^u] = e^u \cdot \frac{du}{dx}$

where $\displaystyle u$ is a function of $\displaystyle x$ - Sep 27th 2009, 08:04 AMmech.engineer.major
thank you