Could someone kindly show me the steps involved in solving the following. y = ln(x/1+x^2) The answer should come out to dy/dx = (1-x^2)/x(1+x^2), but I don't know exactly how this was achieved.
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Originally Posted by nautica17 Could someone kindly show me the steps involved in solving the following. y = ln(x/1+x^2) The answer should come out to dy/dx = (1-x^2)/x(1+x^2), but I don't know exactly how this was achieved. First remember the property of logs that so we get Now using the chain rule we get Now simplifying we get
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