Please anyone show me the way the proof this!

Curl (au) = a dot curl (u) +udot crul (a)where a is a scalar anduis a vector.

All I can think of is to just use the product rule.

Printable View

- Sep 26th 2009, 02:04 AMoxxiissiixxoProof for the div (scalar times a vector)
Please anyone show me the way the proof this!

Curl (a**u**) = a dot curl (**u**) +**u**dot crul (a)where a is a scalar and**u**is a vector.

All I can think of is to just use the product rule. - Sep 26th 2009, 12:35 PMoxxiissiixxo
I editted my post because i wrote the question wrong and it should be

Curl (a**u**) = a dot curl (**u**) +**u**dot crul (a)where a is a scalar and**u**is a vector.