1. ## Limit question

As limit x approaches -3 from the left hand side (x+2)/(x+3), The limit is positive infinity.
And if it approaches -3 from the right hand side its negative infinity.
Why is that ? Could someone please explain it to me?

2. Simple. Since you approach from the left of -3, try to think of a number right next to -3, like -3.1
Then, you see that If you solve for that number, your value in the denominator will be a very small negative number.
Then, in the numerator the number will be a negative number.
So, since you divide a number by a very small number that is extremely close to zero, you get infinity, and since both are negative, they cancel and you get possitive infinity.

3. Why not take a look at the graph of the function? The reasoning will be obvious...

4. Originally Posted by letzdiscuss
As limit x approaches -3 from the left hand side (x+2)/(x+3), The limit is positive infinity.
And if it approaches -3 from the right hand side its negative infinity.
Why is that ? Could someone please explain it to me?
$y = \frac{x+2}{x+3} = 1 - \frac{1}{x+3}$ is a hyperbola and it's graph will give the answer to your question.