Help with differentiating a ln.

**el123** · September 25th 2009, 03:53 PM

$-\ln(2x^2+2y^2+1)$

Having a bit of trouble with this , need to find stationary points.

Im not sure i'm differentiating it right.

$\frac{\partial}{\partial x} -\ln(2x^2+2y^2+1) = \frac{1}{(2x^2+2y^2+1)}\cdot \frac{\partial}{\partial x}(2x^2+2y^2+1)$

is that how i go about it?

**mr fantastic** · September 25th 2009, 06:13 PM

Originally Posted by el123

$-\ln(2x^2+2y^2+1)$

Having a bit of trouble with this , need to find stationary points.

Im not sure i'm differentiating it right.

$\frac{\partial}{\partial x} -\ln(2x^2+2y^2+1) = \frac{1}{(2x^2+2y^2+1)}\cdot \frac{\partial}{\partial x}(2x^2+2y^2+1)$

is that how i go about it?

Yes, except you lost a negative .....

**el123** · September 25th 2009, 07:26 PM

ok gotcha.Thanks.

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