Originally Posted by
mark1950 @Prove it
Dude, if I knew how to solve it, I would not have posted this question here.
@Mr. Fantastic
Thanks. After this step, I simply do not know how to continue. I tried substituting dy/dx into them but simply couldn't get rid of the exponential, e so as to prove that its right. You know what I mean, right?
$\displaystyle \frac{dy}{dx}
= \frac{1}{2}(e^{2x} - 4x + 3)^{-\frac{1}{2}}(2e^{2x} - 4) $
$\displaystyle = \frac{e^{2x} - 2}{\sqrt{e^{2x} - 4x + 3}}$
$\displaystyle \frac{d^2y}{dx^2}
= \frac{(e^{2x} - 4x + 3)(2e^{2x}) - (e^{2x} - 2)^2}{\sqrt{(e^{2x} - 4x + 3)^3}}$