Because is and the series...
(1)
... converges for , also the series...
(2)
... converges for . Ther only difference is that the series (2), unlike the (1), converges also for ...
Kind regards
Hi, I'm trying to do this question, but I'm stuck.
Find the radius and interval of convergence of the series:
x^2n/(n(ln(n))^2)
The summation from 2 to inifinity.
I applied the ratio test and got that the limit equals abs(1/x^2). Applying the inequality I got abs(1/x^2) < 1.
I'm stuck here, because shouldn't the radius of convergence be 1? According to the inequality, the series will converge on two intervals: [-inf, -1) and (1, inf].
Some help would be greatly appreciated.