Using the substitution , or otherwise, find when and now then the answer i would get would be but the answer is supposed to be which cannot be arrived at from as an inverse trig is needed thanks
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Originally Posted by arze [snip] Using the substitution , or otherwise, find when and [/snip] Everything seems ok, except you integrated the last integral incorrectly. You should have gotten
integration of (1/9+t^2) is not ln(9+t^2)....you need to use this formula for that purpose... integral of [1/ (a^2 + x^2) ] = (1/a) . arctan (x/a) hopefully that will help! ohh and arctan is the same as (inverse tan) ... Good luck!
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