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Math Help - please help me with this integral

  1. #1
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    Sep 2009
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    please help me with this integral

    i need help solving the integral x^3 sqrt[4x^2-x^4] dx with limits from 0 to 2...should i use a trig substitution formula to solve? the cosine formula? i'm a bit confused. how would i do that exactly?
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  2. #2
    Banned
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    Sep 2009
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    x^3 sqrt[4x^2-x^4] dx = x^4 sqrt[4-x^2] dx

    x = 2 cost
    dx = 2 sint dt

    hence 64(cos^4t)(sin^2t)dt

    and you can proceed from here..
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